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1.4.8.5 Self-Referential MacrosA self-referential macro is one whose name appears in its definition. A special feature of ANSI Standard C is that the self-reference is not considered a macro call. It is passed into the preprocessor output unchanged. Let's consider an example:
where `foo' is also a variable in your program. Following the ordinary rules, each reference to `foo' will expand into `(4 + foo)'; then this will be rescanned and will expand into `(4 + (4 + foo))'; and so on until it causes a fatal error (memory full) in the preprocessor. However, the special rule about self-reference cuts this process short after one step, at `(4 + foo)'. Therefore, this macro definition has the possibly useful effect of causing the program to add 4 to the value of `foo' wherever `foo' is referred to. In most cases, it is a bad idea to take advantage of this feature. A person reading the program who sees that `foo' is a variable will not expect that it is a macro as well. The reader will come across the identifier `foo' in the program and think its value should be that of the variable `foo', whereas in fact the value is four greater. The special rule for self-reference applies also to indirect self-reference. This is the case where a macro x expands to use a macro `y', and the expansion of `y' refers to the macro `x'. The resulting reference to `x' comes indirectly from the expansion of `x', so it is a self-reference and is not further expanded. Thus, after
`x' would expand into `(4 + (2 * x))'. Clear? But suppose `y' is used elsewhere, not from the definition of `x'. Then the use of `x' in the expansion of `y' is not a self-reference because `x' is not "in progress". So it does expand. However, the expansion of `x' contains a reference to `y', and that is an indirect self-reference now because `y' is "in progress". The result is that `y' expands to `(2 * (4 + y))'. It is not clear that this behavior would ever be useful, but it is specified by the ANSI C standard, so you may need to understand it.
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